Integrand size = 23, antiderivative size = 211 \[ \int (e x)^m (a-b x)^{2+n} (a+b x)^n \, dx=-\frac {(e x)^{1+m} (a-b x)^{1+n} (a+b x)^{1+n}}{e (3+m+2 n)}+\frac {2 a^2 (2+m+n) (e x)^{1+m} (a-b x)^n (a+b x)^n \left (1-\frac {b^2 x^2}{a^2}\right )^{-n} \operatorname {Hypergeometric2F1}\left (\frac {1+m}{2},-n,\frac {3+m}{2},\frac {b^2 x^2}{a^2}\right )}{e (1+m) (3+m+2 n)}-\frac {2 a b (e x)^{2+m} (a-b x)^n (a+b x)^n \left (1-\frac {b^2 x^2}{a^2}\right )^{-n} \operatorname {Hypergeometric2F1}\left (\frac {2+m}{2},-n,\frac {4+m}{2},\frac {b^2 x^2}{a^2}\right )}{e^2 (2+m)} \]
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Time = 0.12 (sec) , antiderivative size = 238, normalized size of antiderivative = 1.13, number of steps used = 11, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.174, Rules used = {137, 127, 372, 371} \[ \int (e x)^m (a-b x)^{2+n} (a+b x)^n \, dx=\frac {b^2 (e x)^{m+3} (a-b x)^n (a+b x)^n \left (1-\frac {b^2 x^2}{a^2}\right )^{-n} \operatorname {Hypergeometric2F1}\left (\frac {m+3}{2},-n,\frac {m+5}{2},\frac {b^2 x^2}{a^2}\right )}{e^3 (m+3)}-\frac {2 a b (e x)^{m+2} (a-b x)^n (a+b x)^n \left (1-\frac {b^2 x^2}{a^2}\right )^{-n} \operatorname {Hypergeometric2F1}\left (\frac {m+2}{2},-n,\frac {m+4}{2},\frac {b^2 x^2}{a^2}\right )}{e^2 (m+2)}+\frac {a^2 (e x)^{m+1} (a-b x)^n (a+b x)^n \left (1-\frac {b^2 x^2}{a^2}\right )^{-n} \operatorname {Hypergeometric2F1}\left (\frac {m+1}{2},-n,\frac {m+3}{2},\frac {b^2 x^2}{a^2}\right )}{e (m+1)} \]
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Rule 127
Rule 137
Rule 371
Rule 372
Rubi steps \begin{align*} \text {integral}& = \int \left (a^2 (e x)^m (a-b x)^n (a+b x)^n-\frac {2 a b (e x)^{1+m} (a-b x)^n (a+b x)^n}{e}+\frac {b^2 (e x)^{2+m} (a-b x)^n (a+b x)^n}{e^2}\right ) \, dx \\ & = a^2 \int (e x)^m (a-b x)^n (a+b x)^n \, dx+\frac {b^2 \int (e x)^{2+m} (a-b x)^n (a+b x)^n \, dx}{e^2}-\frac {(2 a b) \int (e x)^{1+m} (a-b x)^n (a+b x)^n \, dx}{e} \\ & = \left (a^2 (a-b x)^n (a+b x)^n \left (a^2-b^2 x^2\right )^{-n}\right ) \int (e x)^m \left (a^2-b^2 x^2\right )^n \, dx+\frac {\left (b^2 (a-b x)^n (a+b x)^n \left (a^2-b^2 x^2\right )^{-n}\right ) \int (e x)^{2+m} \left (a^2-b^2 x^2\right )^n \, dx}{e^2}-\frac {\left (2 a b (a-b x)^n (a+b x)^n \left (a^2-b^2 x^2\right )^{-n}\right ) \int (e x)^{1+m} \left (a^2-b^2 x^2\right )^n \, dx}{e} \\ & = \left (a^2 (a-b x)^n (a+b x)^n \left (1-\frac {b^2 x^2}{a^2}\right )^{-n}\right ) \int (e x)^m \left (1-\frac {b^2 x^2}{a^2}\right )^n \, dx+\frac {\left (b^2 (a-b x)^n (a+b x)^n \left (1-\frac {b^2 x^2}{a^2}\right )^{-n}\right ) \int (e x)^{2+m} \left (1-\frac {b^2 x^2}{a^2}\right )^n \, dx}{e^2}-\frac {\left (2 a b (a-b x)^n (a+b x)^n \left (1-\frac {b^2 x^2}{a^2}\right )^{-n}\right ) \int (e x)^{1+m} \left (1-\frac {b^2 x^2}{a^2}\right )^n \, dx}{e} \\ & = \frac {a^2 (e x)^{1+m} (a-b x)^n (a+b x)^n \left (1-\frac {b^2 x^2}{a^2}\right )^{-n} \, _2F_1\left (\frac {1+m}{2},-n;\frac {3+m}{2};\frac {b^2 x^2}{a^2}\right )}{e (1+m)}-\frac {2 a b (e x)^{2+m} (a-b x)^n (a+b x)^n \left (1-\frac {b^2 x^2}{a^2}\right )^{-n} \, _2F_1\left (\frac {2+m}{2},-n;\frac {4+m}{2};\frac {b^2 x^2}{a^2}\right )}{e^2 (2+m)}+\frac {b^2 (e x)^{3+m} (a-b x)^n (a+b x)^n \left (1-\frac {b^2 x^2}{a^2}\right )^{-n} \, _2F_1\left (\frac {3+m}{2},-n;\frac {5+m}{2};\frac {b^2 x^2}{a^2}\right )}{e^3 (3+m)} \\ \end{align*}
Time = 0.13 (sec) , antiderivative size = 172, normalized size of antiderivative = 0.82 \[ \int (e x)^m (a-b x)^{2+n} (a+b x)^n \, dx=\frac {x (e x)^m (a-b x)^n (a+b x)^n \left (1-\frac {b^2 x^2}{a^2}\right )^{-n} \left (a^2 \left (6+5 m+m^2\right ) \operatorname {Hypergeometric2F1}\left (\frac {1+m}{2},-n,\frac {3+m}{2},\frac {b^2 x^2}{a^2}\right )-b (1+m) x \left (2 a (3+m) \operatorname {Hypergeometric2F1}\left (\frac {2+m}{2},-n,\frac {4+m}{2},\frac {b^2 x^2}{a^2}\right )-b (2+m) x \operatorname {Hypergeometric2F1}\left (\frac {3+m}{2},-n,\frac {5+m}{2},\frac {b^2 x^2}{a^2}\right )\right )\right )}{(1+m) (2+m) (3+m)} \]
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\[\int \left (e x \right )^{m} \left (-b x +a \right )^{2+n} \left (b x +a \right )^{n}d x\]
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\[ \int (e x)^m (a-b x)^{2+n} (a+b x)^n \, dx=\int { {\left (b x + a\right )}^{n} {\left (-b x + a\right )}^{n + 2} \left (e x\right )^{m} \,d x } \]
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\[ \int (e x)^m (a-b x)^{2+n} (a+b x)^n \, dx=\int \left (e x\right )^{m} \left (a - b x\right )^{n + 2} \left (a + b x\right )^{n}\, dx \]
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\[ \int (e x)^m (a-b x)^{2+n} (a+b x)^n \, dx=\int { {\left (b x + a\right )}^{n} {\left (-b x + a\right )}^{n + 2} \left (e x\right )^{m} \,d x } \]
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\[ \int (e x)^m (a-b x)^{2+n} (a+b x)^n \, dx=\int { {\left (b x + a\right )}^{n} {\left (-b x + a\right )}^{n + 2} \left (e x\right )^{m} \,d x } \]
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Timed out. \[ \int (e x)^m (a-b x)^{2+n} (a+b x)^n \, dx=\int {\left (e\,x\right )}^m\,{\left (a+b\,x\right )}^n\,{\left (a-b\,x\right )}^{n+2} \,d x \]
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